# Line slope calculator 6x+y=42

**Straight line given by points A[6; 6] and B[7; 0]**

## Calculation:

**Slope-intercept form of line:**y = -6x+42

**Canonical form of the line equation:**6x+y-42 = 0

**Parametric form of the line equation:**

x = t+6

y = -6t+6 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = 42

**Distance line from the origin:**d

_{0}= 6.9048

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[6.5; 3]

**Perpendicular Bisector equation:**x-6y+11.5 = 0

**Vector OA = (6; 6) ; |OA| = 8.4853**

**Vector OB = (7; 0) ; |OB| = 7**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 45° = 0.7854 rad**